0.5x^2+0.2x+.16=0

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Solution for 0.5x^2+0.2x+.16=0 equation: 



0.5x^2+0.2x+.16=0

We add all the numbers together, and all the variables

0.5x^2+0.2x+0.16=0

a = 0.5; b = 0.2; c = +0.16;
Δ = b2-4ac
Δ = 0.22-4·0.5·0.16
Δ = -0.28
Delta is less than zero, so there is no solution for the equation

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